Binomio per binomio n°2
Prof. Mauro La Barbera
Risolvere le seguenti moltiplicazioni polinomiali:
| (2a + b)(a + 4b) = | 2a² + 9ab + 4b² |
| (7a + 3b)(a – 4b) = | 7a² – 25ab – 12b² |
| (5a – 3b)(2a + b) = | 10a² – ab – 3b² |
| (a – b)(a – 7b) = | a² – 8ab + 7b² |
| (5a + 2b)(4a + 3b) = | 20a² + 23ab + 6b² |
| (2a – 9b)(a + 6b) = | 2a² + 3ab – 54b² |
| (11a – b)(a + 3b) = | 11a² + 32ab – 3b² |
| (a – 2b)(a – 7b) = | a² – 9ab + 14b² |
| (8a + 5b)(11a – 8b) = | 88a² – 9ab + 40b² |
| (6a + b)(4a + b) = | 24a² + 10ab + b² |
| (3a + 2b)(2a – 5b) = | 6a² – 11ab – 10b² |
| (a + 2b)(a – 4b) = | a² – 2ab – 8b² |