Somma algebrica di monomi

Prof. Mauro La Barbera

  
+ 3a – 7a + 11b – 3b =
+ 5a – 7a – 8a + 6b – 2b – 10b =
– 4a + 6c – 5a + 8c =
– 9a + 3a – 12a + 21a =
+ 12a – 5a + 6a + a – 18a =
– 2b – 5b – c + 4c =
– a – 5b – c + 8a =
– 5a + 3b – 3b + 6a =
– 6a + 12a – 8a =
– 9a + 4b – 12b + 8a =